Решение на Първа задача от Петя Делчева
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Резултати
- 3 точки от тестове
- 0 бонус точки
- 3 точки общо
- 7 успешни тест(а)
- 7 неуспешни тест(а)
Код
Лог от изпълнението
FFF.FF....F.F.
Failures:
1) Integer#prime? checks if a number is prime
Failure/Error: 0.prime?.should eq false
expected: false
got: true
(compared using ==)
# /tmp/d20131023-4395-sjeyk3/spec.rb:4:in `block (2 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
2) Integer#prime_factors constructs an array containing the prime factors in ascending order
Failure/Error: 360.prime_factors.should eq [2, 2, 2, 3, 3, 5]
expected: [2, 2, 2, 3, 3, 5]
got: [2, 3, 4, 5]
(compared using ==)
# /tmp/d20131023-4395-sjeyk3/spec.rb:19:in `block (2 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
3) Integer#prime_factors works with negative numbers
Failure/Error: (-4).prime_factors.should eq [2, 2]
expected: [2, 2]
got: []
(compared using ==)
# /tmp/d20131023-4395-sjeyk3/spec.rb:27:in `block (2 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
4) Integer#digits constructs an array containing the digits of a number
Failure/Error: 0.digits.should eq [0]
expected: [0]
got: []
(compared using ==)
# /tmp/d20131023-4395-sjeyk3/spec.rb:44:in `block (2 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
5) Integer#digits works with negative numbers
Failure/Error: (-33).digits.should eq [3, 3]
expected: [3, 3]
got: []
(compared using ==)
# /tmp/d20131023-4395-sjeyk3/spec.rb:51:in `block (2 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
6) Array#drop_every drops every n-th element from an array.
Failure/Error: (1..10).to_a.drop_every(3).should eq [1, 2, 4, 5, 7, 8, 10]
expected: [1, 2, 4, 5, 7, 8, 10]
got: [1, 3, 4, 6, 7, 9, 10]
(compared using ==)
# /tmp/d20131023-4395-sjeyk3/spec.rb:91:in `block (2 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
7) Array#combine_with combines two arrays by alternatingly taking elements
Failure/Error: [:a, :b, :c].combine_with([1, nil, 3]).should eq [:a, 1, :b, nil, :c, 3]
expected: [:a, 1, :b, nil, :c, 3]
got: [:a, 1, :b, :c, 3]
(compared using ==)
# /tmp/d20131023-4395-sjeyk3/spec.rb:110:in `block (2 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
Finished in 0.02378 seconds
14 examples, 7 failures
Failed examples:
rspec /tmp/d20131023-4395-sjeyk3/spec.rb:2 # Integer#prime? checks if a number is prime
rspec /tmp/d20131023-4395-sjeyk3/spec.rb:18 # Integer#prime_factors constructs an array containing the prime factors in ascending order
rspec /tmp/d20131023-4395-sjeyk3/spec.rb:26 # Integer#prime_factors works with negative numbers
rspec /tmp/d20131023-4395-sjeyk3/spec.rb:43 # Integer#digits constructs an array containing the digits of a number
rspec /tmp/d20131023-4395-sjeyk3/spec.rb:50 # Integer#digits works with negative numbers
rspec /tmp/d20131023-4395-sjeyk3/spec.rb:87 # Array#drop_every drops every n-th element from an array.
rspec /tmp/d20131023-4395-sjeyk3/spec.rb:103 # Array#combine_with combines two arrays by alternatingly taking elements
История (4 версии и 0 коментара)
Петя обнови решението на 14.10.2013 10:10 (преди около 11 години)
Петя обнови решението на 14.10.2013 10:15 (преди около 11 години)
Петя обнови решението на 15.10.2013 00:10 (преди около 11 години)
Петя обнови решението на 15.10.2013 23:47 (преди около 11 години)